22 
RorinJaNz found namely recently (Z. f. ph. Ch. 87, p. 635) for 
Ty, resp. 797°, 904,°5 and 1101? absolute. 
The sign of inequality in the above relation refers to the solid 
state, and as bj == 250 X 10-5 has already been found by another 
way (See Treatise I), the factors 1,67 or 1,75 will have to be raised 
to 1,8 or 1,9. [In what follows we shall have to take this into 
account, and (for solid compounds) we can replace the sign of 
inequality by the sign of equality by increasing the factor 2—m 
by about 10°/, |. . 
For the antimonium compounds we then get (see § 3): 
SbCl, : 
1,8 226,58 
Ki = 0,00595, 
Dy = ET = 
22412 3,06 
hence Sb = 595—345 = 250 & 10-°. 
SbBr, : 
1,9 _ 359,96 ae 
bk = == (),00736, 
22412“ 4,15 
giving Sb = 736—495 = 241 « 105. 
Sbl, : 
1,9 500,96 
bk = 0,00908, 
~~ 2042s”: 466 
hence Sb = 908 — 660 — 248 x 10-5. 
For the density of Sbl, that of the monoclinic form has been 
taken. That of the hexagonal form (2, = 4,85) would have given 
too low a value. Now the results are in very good concordance 
with the value 250 x 10-° calculated before — a proof that (1) or 
(la) is very suitable for the calculation of bj. In this we can also 
bring the value of y to 1,09 instead of augmenting the factor 2—m 
(y==1) by 10°/, (see above). For substances with critical tempe- 
ratures of 800 or 1000? abs. the (reduced) coefficient of direction 
of the straight diameter can, namely, exceed unity. Instead of (la) 
we had better take then according to {1): 
BE == 0, OABEE Ay oe een he KEN 
As factor of v, with m—'/, this yields then the value 2,18 — 
— 0,38 = 1,8, and with m='/, the value 2,18-—0,28° = 1,9, which 
factors agree with what was found above. 
From formula (2), i.e. a, = (7; : 78,03) X bp, the following va- 
lues now follow immediately for the three said compounds. 
