Groups B 
Groups F 
0.93 X= +096 + 0'43 
+ 0.52 + 0.36 
+ 0.04 + 0.59 
10.22 + 0.35 
Mean: + 0'52 + 043 
X= + 0"56 + 0'46 
From c cos db = — (0.93 + 0.20 cos? dj Y 
Y may be determined. The following values were found: 
Groups B Groups F 
Fe obo — 1"59 
— 2.08 — 0.94 
— 2.94 — 1.52 
— 1.66 — 2.08 
Mean: — 238 _ BEES 
The equation . 
a’ = — (0.93 + 0.10 cos? d) Z 
gives the unknown 
Z. The results are as follows: 
Groups B 
Groups F 
Z— +1"45 + 2"35 
+ 3.16 + 4.10 
+ 1.14 + 3.10 
+ 2.17 + 1.30 
Mean: | a 192 a 2"59 
From b' = 0.93 Y sind 
a second value for Y may be deduced. 
I find the following values, in which the fact has been taken into 
account that the weights of the values for Y obtained from the 
4 catalogues are very divergent in consequence of the factor sind: 
Groups B Groups F 
054 Y= —16 =< 1106 
042 Y= 1:35 Ed 08 
0.24Y—= —1.04 = 1590 
0.75 Y= —2.31 ara 
Mean: Y= 3"01 TSG 
Finally from the equation 
c’ = An + (0.93 + 0.20 cos? d) X sin d 
An can be deduced, if the 
substituted in it. 
I find thus for An (STRUVE-PETERS) : 
value for X found from the R.A. is 
