231 
where y continuously takes all values from 0 to a. The constant 
C is a function of its index. It becomes infinitely small in case n 
is infinite, for 7, e.g., being expressed by an infinite series, has a 
finite value for each value of ¢. Therefore we have 
C, = C(¢) dp 
C, = C(2p) dy 
Cy = C(kep) dip 
Substituting this in (8) and introducing 7, =1, 7, =72,=...=7,=0, 
we find: 
dp C (dp) sin (dip) + dep C(2dp) sin (2dp) + ...4-dg C(kdp)sin(kdg) + ...=1 
dp C(dp)sin(2dp) + dep C (2d) sin (4dp) +... 4+-dpC (kdp)sin(2kdp) + ... =0 
dp C(dp)sin(ldip) + dp C(2d p)sin(2ldp) +…+ dpU (kdp)sin(kldp) +... =0 
or 
few singpdg=1 
0 
TT 
fo sin Zpdp = 0 
0 
7 
fem sin lep dp =— 0 
0 
These equations can be solved. by 
2 
Cp) = — sing 
” 
for 
TT 
2 
= {sin pdp=l 
NT 
0 
and 
2 
= fain pain lp d= OF (sj 
7 
0 
For the exponents in (7) we find 
