450 
2 25 
078 073 
dij % oe (in the casei H=4,j == 4), — 2% ark -(in the casei=|= 4, 7 = 4), 
Ai 
_ vr; 
7 
—ds% (in the casei = ) = 4). 
ae 
We now substitute the second term of (2) into the first part of 
2¢7;;. This yields an expression similar to (4), the difference being 
only that #2 and 6 occur in it instead of x and >. We easily find 
: . , : 0d dd 
in the case 1 S= 4,j In 4: -- x le haere ds op cw é (order 2) 
& OW; FO) 
al ee tet Cae 3 (beers 
Ue te GUNG i —— S62. — , order 1} 
: Ou) Ox} Ow, , ») 
. ; 2 sees Orr 4) 
inthe tase, 4 === 4 Bela ; (order 2) 
(1) Ow On) 
Substitnting the fourth term of (5) in the first part of 2G;; we get 
Oy: ° 0 j Oy 
in the casei= == ==. „zl HERAS ah Ti en Sl a 
wd (da? da0x; Ow Ow; 
ay 
-|- dele Ci/ ‚ (order 2) 
| Ow 0a, 
in the case i= =A, 4 == AN er; 
in the case i=) = 4: -27 Ay,,.. (order 2) 
We further must substitute the third term of (2) in the first part 
of 2G;;. Now we have gij =0(1==)) and BU =p? =p" PSD. 
So the third term of (2) becomes 
ee | a 
= P 
and the corresponding part of 2G;; will be- 
ee -(8 ig Ni 0 2| + 
mL) -anl@Le Ji 
stu BERNE 2 NT B dG bo OR Bes 
Siig! on ¢ ae we x= (2 re Bu ae 
DES ifs (2 =) Ed re He t a) 
Tas UP ae er ie Nt a) de, \" da, J’ 
- 
3 
where the term — dj; «° ‘(Ce ) being of the third order, is omitted. 
U, 
EN onder 
We so obtain 
0p Op dee 0 
inthe 84. id Js ae me a Ss gen 
© dv; Ow; (l) Ow l 0x) 
an the case 1=|= 4, 9 == 4: zero 
At 3 
ECE dee VIE Ee (3 =), 
(1) Oar 0x, / 
