492 
an ARS Je Ja? 
§ (8) = TAD Ll Dr 1, (2, DS legd, (2,0): 
v 
If 7 (0) =/= 0, we replace in (2) f (y) by the polynomium 
For) —f (0) which leads to 
ae ee aif (0) : 
=—= | f(y) dy + EL — (AU) — (0) log 2 + 
0 
1 1 1 
foe i! a ee *#y)—7(0) EN l x zm 
+ 7(9) pape ah dy + INDIO) 4) (4) BA dy 
Ag 2 y ; : go 2 2 
0 7 0 0 
1 
Jt 1 
= =F [ied + FO — PC) ly? + FO) ley + 
0 
1 
1 
Hy)—7(v 2: 1 ed ary 
+ {f° WW) dy — | 7 (4) — — cotg — |dy 
y ga oe 
0 0 
and, in consequence for /(y) = (1 — y)", in which » represents an 
integer positive number, 
2t\" 1\/21\? 
of 1+—} + aire — | —l 
“8 n 22 )\ x la dÌ 
zi n ] 
al Eg ea 
eo ee ete ae 
U 
This formula contains the relation 
an 
— 
( 
5 (3) =—- (G—log a + 12,4) 
particularly. If we now choose the height of the rectangle Zar in 
which 1 >« > 0, the method already followed twice before, produces 
the relation 
el 
0 0 
eee pene t fess ! 
if 2aia f Jana 
ee da en 
en ria fw) dy + xa | f(y)eotg nay dy, 
0 0 
if f(y) represents a polynomium in y and f(0)=0; if however 
J (0) does not disappear, we arrive, by replacing f (4) in this relation 
by f 4) — f (0), at the formula 
