| 
eg We sl 2 | ch ee | 2 x Y 2 
n | 
Bo 08 | 45 | 28 65 | 22 
= 9,085" 4 — 0.502 Sei 
2601" Bee 46 | 24 66 | 20 | 
| — 1.820 — 0.449 | -+ 0.837 
27 3 47 41 67 194 
— 1.707 — 0.363 || + 0.910 
28 1 48 25 68 18 
13675 ese, 314 + 0.987 
29 4 49 20 69 13 
— 1.576 — 0.276 + 1.052 
30 5 50 30 70 22 
— 1.485 — 0.220 || + 1.187 
31 5. ol 32 71 1055 
Rell — 0.165 + 1.266 
94 6 ee 2 30 72 7 
— 1.343 — 0.108 + 1.332 
33 10 53 35 | 93 SE 
— 1.249 — 0.046 + 1,364 
34 6 54 32 | "94 "i 
— 1.22 | A0 0d all 1.456 
35 11 55 41 | Pe) 8 
— 1.126 + 0.094 + 1.598 
36 7 56 37 76 3 
Pale hee + 0.160 +. 1.670 
3]. |. ties BT. | 42 | qT 
— 1.026 | + 0.237 + 1.777 
38 16 58 | 24 18 2 
— 0.951 + 0.282 + 1.875 
39247 59 32 ag 7 2 
— 0.882 + 0.344 | + 2.035 
40 22 60 41 80 0 
0808 >} + 0.427 +. 2.035 
41 20 61 34 Sl 0 
— 0.740 + 0.502 + 2.035 
42 23 62> "538 82 0 
| — 0.613 | + 0.519 | + 2.035 
43 11 |. 363° 1 29 || 83 1 
— 0.643 || + 0.654 | + 2.185 
44 | 30 | Wes iA al 1S | 84 0 
SUS Te | + 0.704 | + 2.185 
45 | 28 | 65 he 22 See 
| | | 
values appeared to be pretty satisfactory. Besides we found «,, = 54 
and 4= 3,36. So the normal function runs: 
z—0 54—0 
B == 3,001 log —: == 9790 wig — 0,403. 
| i= ims) LOE 
The reaction-function is 
n= 95 e—x’. 
The elementary increment consists of a positive part proportional 
to the length already reached and of a negative part, corresponding 
to a shrinking, proportional to the 2°¢ power of the length. Supposing 
the growing stalk to retain the same shape, this stunting part is 
