287 
dx 
§ 10. Determination of (=). 
U/t 
Let us now differentiate the relation (c), ie. a= f(v,7) at T 
constant with respect to v, again taking into account that 6= f (wv‚x) 
and a= f(x). We then get: 
0b Ob\ da 
oee 
de 
BEES Balder pet 
NER 1 do 2e 
i IG + areal he 4 
| 5g "142 dv 
| Ab de ; (Le) Ab, 2a. kn Awa)’ da 
B(v—b,) dv | B dv \v—b RTv? | RTv dv’ 
1 ba wil 
because ———_ TEEN can also be written for Ren j (see $ 9). As further 
5 = (5). (5 en 3) b, te fie 
=) ahd ba =z In (see $ 9), 
we get: 
1 Ce dal Ab, dx 
Bir ays ei ey gee ae tea ae 
da 
Tenpin | 
ed A b, de (1+2) Ab, dv 2Yahya (Aa) da 
B (vw —b,) do te (vb) RTv? RTv dv’ 
or also 
Melle) Ab, (1+2)(4b,)% 24 ya) 
a (1-- 2?) BEEN Beb RTs sld 
sl baal l(d+2)Ab, 2Va.A wa 
Sb Saat): RTv’ 
When to obviate unnecessary complications in what follows, we 
disregard all the terms with Ab, — which may the sooner be 
done, as at the limiting volume v, = 6, the volume of :/, double 
molecule will probably be equal to that of 1 single molecule, and 
as besides Aj/a is very large with regard to Ab, — we thus get: 
ll 2V¥a.AYa 
(F)= 2 v—b RTv 
dok 1+ %/,e(l—#) 2(Aa) 
x (1—a?) RTv 
