671 
S, (t/a) =t + fe t) S(t/a) dr 
0 
t 
S, (t/a) = 1 + fs (t/a) dr. 
0 
In this: 
S (t/a) =aF'!(t) + a? F@) (t) +... + ak FAY 
t Ei 
—FO@M=t +f a8, fw (S.) a5, 
0 0 
Fe) (t) = [Fo (6,) FO) GE) dé, 
0 
FO) () = ef Fl (8) FY) (t—£,) dé, 
0 
=d da je 
a (F)_, a (%):=0 
When now specially as moment zero a moment is chosen, at 
and further 
which the velocity ap DS Ze will also become zero, so that the 
( 
solution passes into: 
e= 68, (t/a) 
Now the condition for damping was: 
; da 
lm = 
t= dt" 
Here the equation becomes: 
dz 5 dS, yee 
zg ee 
Hence we get as conditions for damping: 
lim S (t/a) =0 
==) 
lim St) (t/a) = 0 
le) 
$ 3. After what we have seen in the preceding paragraphs about 
the linear system, I shall now proceed to demonstrate in general 
