4S 



Division gives: 



7 7 " 



g^^^ZÜ: :^ 2 (1 - 6',) + (v/c - hl) -— ^ , 



hence, putting vih'^k • (1 — b'i) = ^'k ■ 



vk-b,, 2(1— 6Ï) 



Vk 



3- A 



Vk 



With — = ?', we get finally : 

 bk 



r—l 2 1-b'k 



3 1-V,A- 

 Further follows from the first of the above equations for RTk 



a 2bk{vk—bky 



(2) 



hence 



RTk 



RTk = 



hk 



bk ' vk'{l-b'k) 



2 8 a 



l-b'k 27 ' bk 



(S) 



We find finally for j^k fi'oni the equation of state by substitution 

 of the value of RTk: 



Pk 



a 2{vk—bk) a a 



'vk—bk 2 



Vk 



1-6' 



— 1 



I.e. 



Pk = 



Then {vk =^ rbk) 



bk 



r l-b't 



1 a 



Ok 



(4) 



r— ly 2. 



— 1 



is found for the quantity s = 



r— 1 2 



~Vu^b'k 



RTk 



r }. 



(5) 



pkVk 



If therefore /;V- and b"k are known, ?• is given by (2), and further 

 RTk, Pk, and s by (3), (4), and (5). Reversely b'k and b"k can be 

 calculated when r and 5 are known. 



Thus e.g. with .? = 3,774 (1 : .9 = 0,265) and r = 2,11 from (5) — 

 as then {r — 1) : r = 0,526 and (r — 1)^ : r' = 0,277 — for 2 : (1 — b'l) 

 we find the value 2,21, hence />'/, = 0,094. P'roui (2) we (hen calculate 

 further i^'k = — 0,44, i.e. Vkb% = — 0,40. 



