88 



vh 

 1 dJ 6'' o 



vh n vh 



J dO vh vh 



(17) 



from which we deduce 



1 



C 



J=— (18) 



vk 



Tlie value of C may be determined, because we liuow that foi' 

 r = the function •/ assumes the value!. Then tlie integral becomes 



I / 7j vh 



\/2jrmO .\X 2;t - and the right hand member C.~-. In connec- 

 tion with v = ~-\y^- this yields: 



2-r 



7/1 



C — h.') 



§ 10. Application to chemical equilibrium. 



We will apply these results for the dei-ivation of a formula for 

 the dissociation equiHbrium of a di-atomic gas. For this purpose we 

 will assume, that n^ free atoms are present in a unit of volume. 

 Each atom has a region v, whose properties are described in the 

 preceding paragraph. When another atom penetrates into the region 

 V, a di-atomic molecule is formed. According to our considerations 

 in the preceding paragraph we have : 



?i^ = Ne ^ . je ^ dmr dms' dmt' = Ne ^^ i^rrmOy!^ . (19) 

 X being unity for free space. The number of particles in one region 

 V amounts to : 



_ ^ /^ _ s, + '/J{ro'+r/-hr,^) 

 ii^.=zAe J e y{r,r^v)dmrdnis'dmt'dri.drsdri^^ 



-77 Oh 



= Ne '^ . 2 zimO . 2 .t - 



ƒ vh 



1 







1) Properly speaking can be a function of v, and therefore we should write 

 for C = /i X F[y), where Y{y) is a function of v, which for v = is unity. In the 

 following, however, we will use the simple solution C=Ji. 



