(41 ) 



so that 



A + V, (1 - CO)' 



A = V, (1 - o>y 



3 — 9 (1 — to) (3a> — 1) 



]■ 



1 - 3 (1 — (o) (3to 



-'} 



From this follows e.g. for at =z 0,9, 0,8, 0,7, 0,6 resp., for A 

 0,022, 0,029, 0,004, 0,029. 



The contact at D. If we put in (26) a; = V„ then 1 — 2.r = 0, 

 and hence: 



(<f + V.) (1 - ^y 



3 + 4 (^ + VJ^ (1 - (o) (1 - 3a>) 







This yields besides to = 1 (the point Cj, also 

 (1 - to) (3to — 1) 



hence 



(2^+1)^ 



^ = V, ± V3 



K 



9 



(2^+1)^ 



For (f = 1 this yields two equal roots to = Vs» which proves the 

 contact at D. For <p «<[ 1 the roots become imaginary, so that then 

 C\C\ no longer cuts the line x='^/^, but keeps continually on its 

 right, whereas for <ƒ ]> 1 two points of intersection are always 

 found. So is e. g. for (p = 2 to := ^Yis (close to Co) and lo = 7^ 

 (lying on the other branch between Cj and C^ (see fig. 2)). 



In order to facilitate the tracing of the different spinodal lines, it 

 is to be recommended to fix the limiting values of x for x = 0, 

 x = l, to=:l, to = 73- ^Iso for x='^/^ it is easy to calculate t. 

 From (lb) follows e.g. for x = 0, g) = 1 -. 



r == 4to (1 — to)^ 



This yields: 

 co=:l 0,9 0,8 0,7 0,6 0,5 0,4 0,333 0,3 0,2 0,1 

 T=0 0,036 0,128 0,252 0,384 0,50 0,576 0,593 0,588 0,512 0,324 



For X =z 1 these values become simply 4 times larger, {(p -}- xy 

 then being = 4. 



For X = 7, we get, 



T = to {1 + 9 (1 — to)^j , 

 yielding : 



oi = l 0,95 0,9 0,8 0,7 0,6 0,5 

 T = 1 0,971 0,981 1,09 1,27 1,46 1,62^ 

 For to = 1 we get simply : 



T == 4.r (1 — x)^ 

 from which follows : 



0,4 0,33 0,3 

 1,70 1,67 1,62. 



