15 
edn, 
and with the aid of (72), into 
9 (¢? —1)? 
bs 
from which ensues, in connection with (71), 
6 Bi (G*—1 
en u(C ek 
9 
Ph =F (—$*+ 207—1) = — 
’ 
sin T C 
or 
a(l+ cost 
sin T 
We choose for ¢: 
B _1— cost ae 
6¢= +i———_=-+tt—, .... .. (88) 
sin T 2 
and find in this manner 
= + PY sec? — 
Now the equations (76) and (77) are incompatible. If they depended 
on each other we should have A,, 90, which has not been sup- 
posed to be the case. 
Equation (77) now runs: 
T 
ast + Agy = — 45,2 sec” ER REN: (86) 
Bringing this equation into connection with Tw, y, 2) = 0, we find 
9 2 = 4 2 2{ 9 2 = 
2A, , sec” — .& = }a,,0,, sec’ — —a,,"| 2 sec caw z 
fa = 
9 { 3 6 ¥ it 9 . © 1 
Me See —— ee NO SCC —— a Co an z 
3 u 11733 13 
À 2 2 2 
These formulae can be used unless either A,, or A,, is zero. 
Therefore we will mention also the expressions for « and y for the 
case A,,—0. Then we have a,,—0O on account of a,,4,, + 
+ a,,A,,—=0. We then find immediately out of (86) the expression 
for 2, out of the second equation (87) in which A,, is replaced by 
a,,@,, the expression for y. So the solution is: 
(87) 
gut 
eh = —— O52 2 Sees 
T Tt T 
9 2 = ons a. 2 J ee eS 
2a,,4,, SEC yg Adang — Bing (2 sec" 1)| a 
ase. fae Gh, = Dd. 
The point O coincides with the centre. 
