48 
5 
i= 5 (17a+15c) , H=4i(4a—B8+ 4c), F=— 2 (19a 21e) 
f,= — 10 (ate) (1844 108+11c) = 10 (a Je) 9, 
A= 301 (ate) (8a—28- de) = 10 (ate) g, 
fy = — 10 (ate) (3la—2PH4le) = 10 (ate) 9, 
f, = — 101 (ae) (Ola —14R 459) = 10 (ae) 9. 
Now, omitting the factor 10 (a + c), we get 
9181 + G2 82 + 9s % + G48, = 0 
wherein the values s may be expressed in function of 7 in this way 
2s, — (16a +100) r, —i(3a—28-+30) r, 
2s, = 1(5a+ 68+ 5e)r, + 10(a+e)r, —1(8a—28+ 3e) 7, 
2s, = —2cr, —i(25a—6B-+ 25¢) 7, 
a= Gat 68-4507, + (Ba4-60)r, + = (7a-+28-+ 7c) r,+(7a+100)r, 
Substituting these values, and putting 
G,=18a+ 1084 Ile , G,=9a— 68+ 15c, 
G, = 3la — 28 + Ale , G, == bla — 148 + 5% 
we find 
1 
r, [— (16a+10c) G, — (5a+ 68 +50) G, + at (Ba + 68-4 de) G,] 
++ ir, [(83a—28-+ 8c) G, + 10(a+c) G, — (5a + 6e) G,] 
1 
+ r,[(8a—28-+ 8c) G, + 2¢G, + a aaah 7c) G,] 
+ ir, [(25a —6BH 25c) G, — (7a+10c) GJ =90 
which may be reduced to 
1 
me [—20la?— %2a8— 252ac—128?— 36fe — 75c*| 
4+ ir,[—176a?+ 14a8— 349ac — 209 H 328e—171e*] 
1 
4 = r,[ 48la?7— 4843 + 1108ac— 48? - 84e 4 667c*] 
+ ir,[ 848a?—188a8+ 777ac + 128? — 156pe 4 4850" | = 0 
Writing this result 
1 DS ry. 1 ~ 7 
a T,+u,T,+ ae Cefn, Ts =0 
and assuming 
a if z 1 
‘soe He IN HeT. 
we obtain 
