789 



tension. In this case (31) will also be ai)plicable; we may then, 

 howevei-, rephice r and q^ by r„ and q,^, in which r, denotes the 

 heat of melting, and q^„ the density of the solid phase in the tension- 

 .less state; then we have 



dT = [(X, -p) d^c^ + (y>/-p) dy,, + {Z,-p) dz, + 



^^10 . (32) 



^ Y.dyz + Z,^dzy: + Xydx,^ . ' 



If we disregard quantities of the second order, which we are 

 allowed to do when we consider the dilatations and distortions 

 as infinitely small, we can integrate (32), placing T. r„, and ^^^ 

 outside the integral sign. We then get for the lowering of the freezing 

 point in the state determined by .iv, ?/,/. z^, y~, Zx, Xy, 



^T = - f[{X,-p) dx, + {Y-p) dy,, + {Z,-p) dz, + 



/ V / 



Yzdy^ -\- Zj^dzj: -[- X^dx,^ 



The heat of melting in the state determined by .r^, ;/,,, z~, y~, z^, .i\ 

 will differ from that in the tensionless state by an amount that is 

 of the same order as the dilatations and distortions themselves. For 

 an infinitely small change follows for the change of (he free enei-gy 

 from (14) : 



dxp= {X^dx:, + Yydyy + Z,dz, + Y,dy, + Z^dz,. + X„dx.) 



Hence the difference in free energy bstween the deformative and 

 the tensionless state amounts to : 

 X;, ... yz ... 



^^P=- f— [X:>:dxx + Yydy>, + Zzdz, + Y,dy, + Z^dz,. + X.dxy]. 







For the difference in entropy between these states follows then 

 from (16) 



.^-.r - yz ... 



Ö fl .. 



Aii 1= — I — [X,dx,. + Yf^dy,, + Zzdzz -f Y.dy^ + Z^^dz^ + X,,dxy]. 







From (27) follows then for the difference in heat of melting: 

 xx ... yz ... 



d ri 



Ar== - T^j-[X,dx,.-{-Yydy,,-^Zzdzzi-Yzdy: + Zxdz,i-Xydx,] (.34) 







