340 NEW SERIES for the 
_ 
ExaMPLe II, The length of an arch of 90°, computed by- 
the fecond feries, (Art. 22.). 
cofa=o ee: a = 0.99518472667.. 
cof + a= 0.7071067811865 cof ,'5 4 = 0.998795456aI.. 
cof +4 = 0.9238795325113- cof ;'; 4= 0.9996988187... 
colt 4 = 0.980785280403. aay 
Amount of pofitive 1 1+ cofa re 5 = .416 666 666 666 7 
terms, 4 —cola ie PISA OS «ne, 
vey ce 
yt era we ae = .010 723 304 703 4 
hee cofta ) 
ai sine eats -000 618 220 7796 
& t—cofta 
4*1+colta 
t r1—colft.a _ 
4°>1+col+.4 
= .000 037 892 7990 
.000 002 356 882 2 
1 100954 — 900 000 147 127 6 
4°1-+cof4 
& Ecole = .000 000 009 1927 
471+ cols,4 
i 00 612 8 
pees feictels Hence = .000 000 000 612 7 
S> .000 g00 000°612 6 
Amount of negative terms, .O11 381 932097 2 
Difference between the apie of Lacgigasaanes 560% 
and negative terms, bee ; 
== 636 619 772 3677 
Arch of 90°, or a= 1.570 796 326.795- 
EXAMPLE 
