151 
and for the V,,: 
4 
K' = 2{V'(a'.c) SV (b'.c)i (a — Db’). (30) 
Dividing a,b and c as in (2), we get: 
8 4 4 
giK = 2g 2{V (A.C) ~ V(b’. c)i (a —b) + 
4 
+2¢g7{V(a.c)— V(b". c’)} (a —b) + | (31) 
5 : 
+ 2g'2 VY (ae) SV (be) | (a — b) + 
4 
+ 9 gi? iV (a’.c’) =~ V (b". c’)} (a joa b’). 
4 
The first of the four terms on the right in (31) is equal to K’, 
the second and third terms are equal, because they pass into each 
other by changing a and b. 
3 
The three last terms can all be expressed in H. For on one side 
we have with respect to (14): 
3 4 4 
Hf" (ce = ¢ 2 )V @ cine — 230 (vc) ac’ 2) 
and on the other side with respect to (5): 
3 4 pi 
H= —g?2{(Va')icacj=— gs? {Va".oja'c= on 
= —*g'1 {V (a".chaec=—g IV (b". db’ d. 
When now we write: 
3 
Hi = H, H, H, — ‘A, H, 'H, ’ (34) 
3 
which is permitted, H being symmetrical in the first two factors, 
we have 
4 
4 
(H, ~'H,) (H, ~'H,) (H, .'H,) = — g'2 VAC) SV (b".d")} (a! b! (c". a") Js 
= — g'2 (VAC!) SV (b".c"}} (a S b+) 
and also 
4 
(H, ~'H,) (H, ~'H, )(H, . 'H,) = 2 {V@a".c') — 7b". a"); A Sb) (Cd) | ee 
4 
= #2 {Vea'.c')~ VO". ea’ Db), 
hence we get: 
(37) 
