95 
Nor is this manner entirely satisfactory; for now we do not know 
to what 2 the found 7’ should properly speaking belong, because 
the two values of 2(2, and 4,), which are required, can lie pretty 
far apart in this way of calculation. Does for (A, = 0.9, A, = 1.8) 
T e.g. belong to 2,, to 2,, or to a value lying somewhere between 
a and AP 
When we want to avoid this difficulty, we may treat the equa- 
tions (6) as follows: 
Let}, 24, De’ ==" Or 
ek 
m 
(9) 
i= = 
n 
we find easily : 
mB 
= : 5 nf 
a a eae 7 
a,/\n Woes (10) 
But: 
Fs 
lie EE) ie (11) 
OAN, 
then (10) passes into: 
am Can + (C—1) = 0 (12) 
When we take care that m is —=n +1, the shape becomes some- 
what more suitable for numerical approximation, namely: 
en(e —C) + (C—1)=0 (12a) 
When z has been sufficiently closely approximated, 7’ follows 
from : 
pz 
el z 
In this way 4, and A, can be brought close enough together to 
exclude indefiniteness in the choice of the 4 to which 7’ belongs. 
Thus we found: 
EEN REE ENNE KEN KE LN TE EEN NET ENT EERDE EEE EET 
0.5 
(13) 
le ROE 0.6 | 0.7 0.8 1.0 1.2 | 1.5 1.8 
zene Gee Cet! A KE | ase eer i 2.0 
7 | (6400) | 9000 =a 9600 | 8000 | 5500 | 3800 | 5400 = 
so that on an average: 
A= 0.5—0.7 T = 9500 
0.7—1,2 6000 
1,2—1,8 _ 4600 
