y calculated. | Found. 
EF =3000= 60.102 V. | 7 =29.77 H 4.99 — 3.24=31.52 | 31.4 + 0.14 
3300 = 7 » 3.82— 4.44=31,.18 | 31.20 | — 0.02 
4000 = 8 » 6.65 — 5.76= 30.66 | 30.70 | — 0.04 
4500 = 9 » 7.48— 7.29=29.97 | 29.99 | — 0.02 
5000 = 10 » 8.32— 9.00=29.09 | 29.40 | — 0.01 
5500 == 11 » 9.15 — 10.89 = 28.03 | 28.00 | + 0.03 
6000 = 12 » 9.98 —12.96=26.79 | 26.72 |J 0.07 
6500 = 13 » 10.81 —15.21 = 25.37 | 25.33 | + 0.04 
7000 = 14 > 11.65 —17.64= 23.78 | 23.79 | — 0.01 
7500 = 15 » 12.48 — 20.25 =22.00 | 22.00 | + 0.00 
8000 = 16 » 13.31 — 23.04=20.04 | 20.01 | + 0.03 
8500 = 17 » 14.14 — 26.01 =17.90 | 17.90 | + 0.00 
9000 = 18 » 14.97 — 29.16 = 15.58 
As we see, formula (6) with these values for a,b andc represents 
the descending branch with extraordinary accuracy. If we leave 
out of account the value for == 3000, which no longer belongs to 
the descending branch, as I have shown above, the difference between 
1 
the calculated and the observed value surpasses nowhere 5 Jos only 
hel 
once (at E= 6000) the difference is T Of. 
If in (6) we substitute for ZE the value 6,04 x 0,102, we get 
y for @=0, i.e. po. So we find 
P‚ = 31,508. 
A k 
In order to calculate EE and en we combine (5) and (6): 
k+B 0,090 
—— =e= == 8.651. 
Pp Tug 
k+ 8 A 0,8318 
pau) ie SS A 
hk? Ao k 0,102 
