(574) 
| y calculated, Found, | A 
E= O=0X0.102V. | y= 25.46 A 9.00 —0.00= 25.46 24.78 ?| + 0.68? 
500 =4 > 9.45 —019=27.42 | 27.40 | + 0.02 
1000=2  » | 4.31 —0.76=29.00 | 29.00 | + 0.00 
1500=3 » 6.46 —1.72=30.20 | 30.20 | + 0.00 
2000=4 » 8.61 —3.05=31.02 | 30,65? | + 0.37? 
2500=5 ~—v 10.77 —4.77= 31.46 | 31.33 | + 0.43 
3000=6 » 12.92—6.86=31.51 | 31.44 | + 0.40 
The values for H=0O and L= 2000, namely y = 24,78 and 
y = 30,65, have been marked with a note of interrogation by the 
experimentator himself; so these values may be left out of conside- 
ration (l. c. page 460 and 467). The greatest difference is then 
about 4 °/,. We have still to mention that for 
E = 3020 = 6,04 x 0,102 Volts 
the values, calculated for a, 6 and ec, yield y= gy = 31,51, as they 
ought to do. The two parabolae meet there. 
For 2 and 5 we find in the same way as above: 
a = = ni = 18,320. 
hay dant 
so putting Ap = — 0,616: 
= ——2 toa < 0,616 + ome = — 22,570-+4+21,108= —1,462. 
A oa 
7 Appears to be negative, j.e. the negative charge (Cl-ions) is 
situated in the solution at the Jd of the bordering layer, and 
not — as the positive charge of the Hen — deeper in that layer. 
For the ascending branch we may write for this case either 
