1074 



If', however, water is aildod, the separation of solid NaCl and 

 NaNOg oan be avoided and the solution d obtained -is the final 

 liquid which has the composition 0,J3 K, 0,87 Na, 0,54 NO3 , 0,46 CI, 

 4,99 H2O. This separation takes place according to the equation 



0,62 K \ iO,13K 



jO,38 Na I \0,87Na 



0,80 NO3 4- 0,371 H,0 = 0,563 KNO3 + 0,437 0,54 NO3 



1 0,20 CI i i 0,46 CI 



'1,81 H,0 ' '4,99H,0 



(PJOO) {d) 



As the solution P„ can be obtained from 0,80 mol. NaNO, and 



0,62 grm. mol. of KCI the yield, in this method of working, is of 



0,563 0,563 



NaNO, ^ X 100 = 70,47„ and of KCI ~ X 100 z= 90,87o- 



' 0,800 0,62 



In a continuous process the final solution d must be again converted 



into the solution P^ (100°) which necessitates addition of fresh NaNOj 



and KCI (in eqnivalent proportions). On heating at 100° these salts 



pass into solution and NaCl is deposited. The entire decomposition 



takes place according to the equation : 



0,13 K ] [0,62 K I 



|0,87Na 0,38 Na [ 



0.437 0,54 NO3 + 0,563 KCI + 0,563 NaNO, = 0,80 NO3 1 + 

 '0,46 CI 0,20 CI 



4,99 H,o) [l,81H,0)- 



{cl) (P, 100) 



+ 0,371 H,0 H- 0,563 NaCl. 



We now have once more the original liquid P^, namely 1 grm, mol. 

 or 122.2 gram, whereas during the circulation process 0,563 grm. mols. 

 NaNOj have been transformed into KNO3. Per 100 gi-ams of the 

 solution P, (100°) this is 0,461 grm. mols. 



IV. If the lowest temperature we work at is not 5° but 25° 

 the final solution becomes: 



d' = 0.29 K, 0.71 Na, 0.627 NO3, 0.373 Cl, 3.87 H,0. 



The transformation of P.^ (100°) into d' takes place as follows : 



/0,62K ] [0,29 K ] 



lo,38Na 1 0,71 Na / 



0,80 NO3 -f 0,26 H,0 =: 0,465 KNO3 + 0,535 0,627 NO3 > . 

 ]o,20Cl I i 0,373 Cl 



[l,81H,ol [3,87 H3O' 



(P, 100°) {d') 



