( 754 ) 
dn 
==> ni — zt, where z is put for — 
at’ 
dn A 1 og 
Fie — Zn — din 
dn Ma 
Te (4zi —#)n + (2? — 32) ú 
( 
d 
From the differential equation rs (r*# + r) = 0, satisfied by 7, we 
at 
can derive the following differential equation for <= —: 
5 
which may serve to eliminate £ from the higher derivatives. 
2 
d° z 8 2 
rset eee 
For t= 0, nm is equal to zero and #= K,, hence 
C : < 5 7 7 ie 2; 
Kak en EK K, = —— KK. 
sed 120 hee 
If we substitute the expressions for the coefficients A in the second 
of the 4 relations, this becomes : 
2 | 1 1 2,°—82 
LS te ic -= — 2,1,” — — 2,c,° He Tee 
and from this it clearly appears that A, and the other coefficients 
a ‘ ; 1 
K, in so far as they depend on the intervals, are of the order —. 
©, 
2 
From the 4 relations with the indefinite coefficients AG, A,, A, we 
find by eliminating the latter : 
Tae Atte 
„ 2 1 2°3 3 3 , 
Bil ¢ 7 Siva 
12 Pe 
From this equation I solve : 
n= iS Es ee! 1 bie F. En 
2 rt | 3 
2 2 
T, +-T,T.—T, 
i 
Dn 3 
__t, 127, R 
DI 5 inn 
Tv, 1 T, TT, —Ts 
127,° 
where 
