( 283 ) 

 we get : 





(1-;?) (l+(r-l)^)-i (l + (r-l)ii)-' (7^7')v-i 



or putting v — 1 = x : 



(r-^/V ... (1) 



If now A/^ is positive, i.e. if the complex molecules (real or apparent) 

 occupy a smaller volume tiian the simple ones, the degree of disso- 

 ciation ji will get the value for v = b, and the \alue 1 for 

 V = X. In the same way the quantity /i will approach to at 

 l^=zO for positive values of qo and y, and at T= go to 1. 



In order to facilitate the following calculations, we put: 



Ab 

 (1+../?) ~ = (p, (a) 



V — b 



in consequence of which (1) passes into 



(\—^){l-^o',^Y (f^ 



(I'O 



£\b\^ V — 



7o 



in which ^ represents the temperaturefunction c I — j T e ^^. 



The equation (1^), combined with the equation of state 



ip + "/r^)(v-b) = {l+.v,3)RT (2) 



will now represent the total amount of the considered substance, to 

 which then b = (1 — {i) b^ -\- r,i è^ can be added, i.e. 



b = vb^ _(l_^-j)A&, 

 or rb.^ being the limiting volume for v ^ go (;?=!): 



b = b, — {l—^)Ab (3) 



in which ^ is given by (l'^), and hb by Ab := ~ b^ -{- rb^. 



Now in order to find the values of v, RT and p at the critical 



/'dp'\ f^^'P\ 



point, we shall onlv have to put — and — equal to 0. 



From the equation (2) in the form 



_(l+.r^)i?r a _<(RT a 

 ^ ~ v — b V^~Kb V 



follows (for T constant) 



dp 2a RT dip 



dv~V''^~Kb~db ^^^ 



