( 285 ) 

 1 



L' — h df3 X -f- 1 



iH^-^)[.^ + *p) 



1 +.P/? dv 1 



So we find linally, substituting (d) in (y) 



1 



(hp Ah .f+l 



rtü r — o 1 



/?(1— /?)(..+ r;r) = 



1 + — 77i^(l-<^)(-'-+^/r 



Ab 



01- as (1+.;'^) - = rp: 



v — b 



dp 2a RT (p 



dv v^ Ab (v — b) 1 



a;-\-l 



d'p 

 As also — must be = O, we have, when the equation 



V — b RT fp 



Ab 1 



is logarithmically differentiated : 



1 f db^ 3 l d<p 1 dy 



i<i) 



d<p cp 



dp 

 Now we get for — , by substitution of this value in ((i) : 

 dv 



(4) 



dvj V if dv \-\-y dv^ 



when for shortness we put the expression ^i(l — iJ){x-\-(p)'- fora 



db d^ 



moment = y. Hence, as — = Aè — : 



dv dv 



^c-b) d3 1 1 dy 



1 Ab — = [v — 6) — , 



V dv ^-\-l/ 1 — y dv 



1 dip (p 

 because (v — o) — is equal to according to (e). Hence we get . 



dv 1+2/ 



. dS dy 



{2J^y)-^lJ^.y)Abj-+{V-b)J- 



V — b dv dv 



3 — _ ^ , 



V l-\-y 



