1205 
increases towards the other side of this line. At the side turned away 
from the point D of the line X/Y is now also found the temperature 
maximum. This is also in agreement with (10). 4 = V—v now 
being negative it follows that for positive values of (Y) and of dg, 
dT from (10) is now negative ; this means that the pressure decreases 
from F towards that side of the line X/Y where the point D is situated. 
i 
We now take a from (5) and write this in the form: 
dP B—RD 
En any) (11) 
dT ARC 
In this: 
in M bei ie a)r mr (u —8)s cos p + (e a)s + (y—Bp)e} sin f . (11a) 
NL (ar, —a)r - (y,——y)st cos gf + fa, — z)s B (7, —)8 sin p 
For «=a and y=g, K=O unless p is chosen in such a manner 
that the denominator also becomes 0; this is the case, when starting 
from / in fig. 1, one moves along FN or FY. We will first assume 
that this is not the case. 
If one moves from F/ towards that side of XY where the point 
D is situated R will be positive; when moving from / towards 
the other side A& will be negative. We now let a liquid saturated 
with solid # proceed along the line Z/'Z,; from (11) it now follows 
that in the point F 
CPAP Det EN 
te en He RE 
AAA V—v ‘ 
