1188 
as the point A, does not represent a phase, we shall draw it on 
the inner side of the cirele. In order to express reaction 54, we place 
the points # and F at the one side, B, C and D at the other side 
of the line AA,. 
Fig. 1 gives a graphical representation of reaction 54 and in such 
a way that any error is excluded. When we had not drawn the 
point A, in it, the representation would be indistinct, as we could 
not know then, to which monovariant equilibrium the reaction related, 
so that we might make six suppositions. This doubt, however, is 
entirely taken away by the point A,; this means that the reaction 
relates to the monovariant equilibrium (A). 
In this way of representing the position of the points # and # 
at the one side and that of the points B, C and D at the other 
side of A is quite arbitrary with respect to one another. Consequently 
it is not allowed to deduce from fig. 1 the reactions which occur 
Zh 
£ 
A 
G B 
Fig. 1. Fig. 2. 
in the equilibria (B), (C) ete. Suppose one wishes e. g. to represent the 
reaction in the equilibrium (C), then for this another figure is wanted, 
in which we draw a point C, within the circle. When this reaction 
happens tobe A+ B+ HZ D-+ PF, we can represent both reactions 
in fig. 1; then we obtain fig. 2. 
As in asystem of 2 components 7 + 2 monovariant equilibria occur, 
we should want 2-2 diagrams for representing those + 2 react- 
ions. We can, however, give to the phases with respect to one 
another such a position, that all reactions can be represented in a 
same diagram. 
Let us take for an example a quaternary system with the phases 
A, B, C, D, Wand F. We assume that herein occur the reactions : 
A+B+D2C+EHE , A+ FRBHCHD 
B4+CHD2ESEF , At+BL+D2EIF!. . (55) 
A+F2B+C+E and A 4 pDirac+eE\ 
