106 



Astronomical and Nautical Collections. 



Example II. 



June 14, 182^, in N. latitude, at 7'' 30" A.M., the sun's altitude 

 and azimuth were 27° and 73°; at 9*" 30"" the same forenoon, his 

 altitude and azimuth 54° 10' and 78°, the mean declination being 

 23° 17'. Required the latitude. 

 To find arc I. 

 1. COS. D' = 9.963108 

 1. sin. 1 E = 9.41299S 

 13° 45' 12" 9.376104 l.s. 

 I =27 30 24 



To find arc II. 

 1. sin. E = 9.698970 

 1. COS. d =r 9.963101 

 1. cosec I — 0.335497 



To find arc V. 

 1. cos. A = 9.767475 

 1. cos. D = 9.963115 

 2.1. sin. IV = 9.656874- 

 const, log. = 0.301030 



N r: 488083 9 688494 

 n. cos. A—D— 858194 



- N =: 488083 



Lat. = 21° 43' 20" 3701 Un.s. 



83 56 .32 

 11=41 58 16 



9.997568 1. s. 



To find arc III. 



1. cosec. I =: 0.335497 



I. sec. A = 0.232525 



l.cos. I S + «= 9.765685 



1. sin. |S^=: 9,662019 



19.995726 



I = 27 30 24 

 A = 54 10 

 S = 81 40 24 

 a— Tl 



III = 84o 19' 15" 9.997863 1. s. 

 II = 41 58 16 



IV =: 42 20 59 



108 40 24 



54 40 24 



\. S + a = 54 20 12 



^.S-a = 27 20 12 



In this Example, the azimuth at the greater altitude is greater 

 than the other azimuth ; therefore the fourth arc is equal to the 

 difference of the second and third arcs, by Rule II. 



