152 Astranumical and NaKfiral Collections. 



Example. 

 To find K and m for Capella 



CAR 1820 = 2. 15° 51' 



s 



■.5" 51' ■) 



iDecli.* 45° 48' N J 



Tab. I = — 1800 log. 1.2553 Tab. III. = +4,96 log. 0. 6955 



Decli. « log. sin » 9. 8555 Log. sin, Decli. » 9.8555 



— 12,90 1.1108 +a' log. 10. 5510 



Tab.II.= + 5,62 —a log. 0.8627 



a = -7,29log. 0.8627 tan. 9.6883 



Ar.Comp.cos. K 0.0463 s 



K=11.4°0' 



7n = 8,ll . . 0.9090 



For -Aberration in AR in Time. 

 Aberration in AR = 7rtCos (K -^ © Long.) 

 log tan K = log tan AR + log sec. 23°. 28' 



K is in the Quadrant opposite to that in which AR is 

 log m = const, log. 0. 1303 + log sin AR + log sec D + 

 log co-sec K 



Example. 



("AR a Cassiopeiae = 7° 35' "^ 



L Decli. = 55°. 33 N J 



tan. 7°. 35' 9. 1243 

 sec. 23 28 10.0375 



i 



K = 6. 8°. 15', tan. 9.1618 



s. ° ' 

 const, log. 0. 1303 © Long. 8. 5. 4. 



sin 7°. 35 9. 1205' K 6, 8.15. 



sec. 55°. 33 10. 2474' 



CO sec: K 10.8432 cos 1.26.49 9.7382 



0. 3414 



m = 2,20 0.3414 



Aberr. in AR= + 1,20 0.0796 



