108 
Example 1. Given A—63°, h=28.54.. Compute B—27°, log a—=1-405337 
25-429) log b——11250! b= 12.:957- 
CHECKS 
AL —— "63> 2ab =— h? cos (A-—B) 
oe log 2 = 0.30103 log hk = 1245545 
lope — te 40553 1.45545 
A-B = 36 ye 9) = al ITD log cos (A—B) = 9.90796—-10 
2.81886 2.81886 
25704 ; 
(a+b) (a—b) = h? sin (A-B) 
@—_ 25,429 
1.58417 1.45545 
pi NOES 57, 1.09594 1.45545 
9 .76922-10 
a+b = 38.386 2.68011 2.68012 
a-U = 12-472 a? = (h+b) (h-b) 
h+a = 53.969 1.40533 1.61802 
2 1.19265 
h—-a = 3.111 2.81066 2.81067 
h+b = 41.497 b2 = (h+a) (h-a) 
h—-b = 15.583 1 11250 1.73214 
2 0.49290 
2.22500 2.22504 
Example 2. Given A = 28° 40’.4, b=20.71 Compute B= 61°19’.6 
log a = 1.057407, a = 11.326, log h = 1.37300, h = 23.605. 
CHECKS 
Bi — Glee O76 2ab = h? cos (B-A) 
Ai Aas 0.30103 1.37300 
1.05407 1.37300 
B-A = 32° 39’.2 1.31618 9.92528-10 
2.67128 2.67128 
ho 2s. 60p 
(b+a) (b-a) = h? sin (B—A) 
pa— Oar 1.37300 
1.50564 1.37300 
a es26 0.97239 9.73204 
2.47803 2.47804 
b+a = 32.036 
a? — (h+b) (h-b) 
b-a = 9.384 
1.05407 1.64655 
h+a = 34.931 2 0.46165 
2.10814 2.10820 
h—-a = 12.279 
b? = (h+a) (h-a) 
h+b = 44.315 1.31618 1.54321 
2 1.08916 
h—-b = 2.895 ——— —-—— 
2.63236 2.63237 
It appears that these checks are not all sensitive to the same degree. Experience 
will assist the computer in choosing the one best adapted to the problem at hand. For 
example, (1) is more sensitive than (2) when the difference of the angles is less than 
45° Stee vice versa. Of (3) that one is better in which the factors are most nearly 
equal. 
