N:o 11] 



tjber die inuere Reibung von wasserlösungen. 



11 



Mannit bei 20" G. 



n=0,5 S = 1,033 



t = 116,85 A t = ±0,05 r = V 



77=1,2963 Bj — B2 — 



n = 0,i s = l,007 



t=98,8 At = ±0,io r = I 



i; = l,0594 Bl— 62 = 1,0533 



n = 0,02 s = 1,001 



t = 105,075 A t = 0,025 r = nr 



7^ = 1,00987 Bl— B., = 1,0105 



Schivefelharnstoff bei 30 " C. 



In 3 = 1,0215 



t = 93,65 A t = — 0,05 r = V 



7? =1,0292 Bi = — B,s^ — 



0,5 n 8^1,0107 



t = 104,70 At = -f0,35 r = ni 



7/ = l,0162 Bi=:l,0145 B2 = — 



0,1 n 8 = 1,0022 



t = 87,5 A t = ±0,15 T = 1V 



??=: 1,0065 B, = 1,003 B2= — 



0,02 n s=== 1,0004 



t = 94,o At = ±0,to r = I 



7^ = 1,0017 B, = 1,0006 Bi^ — 



starke bei 30" C. 



17o 8 = 1,012 



t = 151,i5 At = + 0a5 r = IV 



7? = 1,7554 B, = — B2 = 1,6875 



0,5 "/o 8 = 1,0063 



t = 119,925 At=- 0,075 r = II 

 7^ = 1,29903 B) =1,3249 B^ = — 



Mannit bei 40 " C. 



n=:0,5 8 = 1,031 



t =75,0 A t = ±0,1 r = V 



7/ = 1,253 I B, = — Bj^ — 



n = 0,i s = l,"06 



t = 64,52 At = + 0,08 r = I 



7^^1,0461 B, = — 62 = 1,0461 



n = 0,02 8 = 1,001 



t = 69,075 A t = — 0,075 r = III 



7^ = 1,0079 Bj = — B, = 1,0091 



Schivefelharnstoff bei 40" C. 



In 8 = 1,0201 



t = 62,10 At = + 0,io r = V 



7; = 1,02647 Bi = — 62 = - 



0,5 n 8 = 1,0104 



t = 68,93 At = ±0,io r = III 



1^ = 1,0143 B, ^1,0133 62 = - 



0,1 n 8 = 1,0020 



t = 58,05 A t = + 0,35 r=^IV 



7^ = 1,003 Bl =: 1,0027 64 = — 



0,02 n 8 = 1,0004 



t = 62,1 At= + 0,20 r = I 



7^ = 1,0003 B, ="1,0005 Bj = — 



starke bei 40 ° C. 



10/0 8 = 1,011 



t = 95,35 At = ±0,05 r = IV 



77 = 1,66204 Bi = — 62 = 1,4863 



0,50/0 8 = 1,006 



t = 74,25 A t = — 0,05 r = II 



77=1,2191 Bi = 1,289 62 = - 



