Survey of Northeast Greenland. 267 
After this the reduction to the meridian is computed by the 
well-known formula о sin”, where for ф, д and z one uses 
approximate values f. inst. ф = 82°26’.2, д = + 16°18’, z = 66°08'.1 
whereas the factor 2 w sin? 5 is taken from a table for the argument t 
(the hour angle) expressed in differences of the clock time. 
MEN En III NN RE ele av 
eh... | 11n33m]2s | 11h39m55s | 11h43m45s | 11h47m45s | 11h51m57s | 11856100 
RE =... | 662135" | 66°21'12”  66°21'06” 66°2103”|  66°21'08"|  66921'14” 
evel N... | + 37 | + 4 |+ 26 33 | + 37 | + 33 
Beers. So: eR OT Ae ло, oe DOT Ne ar 
Е. RON 3601 |= 160 |= 160r вм 
Geocentric z.... | 66 0838 | 660742 | 660758 | 66 0802 | 660811 | 66 0813 
ая | On Er ar CAE и + 13 hee 16 
ee ne s ES Gees aes ees 10 |= 28 
meridian J | | 
д (11h33m19s).... | 16 1800 |-+16 1800 |+16 1800 |+16 1800 | +16 1800 | +16 1800 
Pe Sr 82 25 55 82 2537 | 82 2605 82 2612 | 82 2614 | 82 2601 
| | | | 
The computation shows what might a priori be expected, that 
the observation II fits very badly into the whole group. If it is ex- 
cluded from the mean, we get ф = 82°26'05” + 8”. 
The mean error indicated must be supposed to be too small, 
among other things because the time of the culmination is deduced 
from the observation series itself. 
Latitude, midnight 15—16/V 1907 (observed by Kocx with- 
out an assistant). ©; b = 769 mm; t = + 15° C.; 1 division of the 
level — 20”; calm. Instrument placed on glare ice in the immediate 
vicinity of the coast off Kap Bridgman. I = about 11467 west of 
Grw.; clock correction $ = — 16™305. 
Telescope left | Telescope right 
| Vernier | Level | | Vernier Level 
Clock time = Glock EME EE Es ce | : 
|, А в | Obs. | Obj. | Е SER | Obs. Obj. 
12h07m05s | 282°38'.6 | 39.3 121 | 60 | 12h09m05s | 77°22'.3 | 23.0 | 2.0 | 85 
13 10 | 38.6 | 39.2 | 13.5 | 68 | 16 25 | 22.5 | 23.2 | 2.5 | 9.0 
19 30 | 38.6 ue | 13.0 | 62 | 21 35 | 22.3 | 22.9 | 120 | 8.6 
| | | | | 
