690 PLATEAU ON THE PHiENOMENA OP A FREE LIQUID MASS 



centimetre as the unit of length, M'e shall have for any value k 

 of this diameter 



e=2k; 



and if we replace k by its approximative value 0*8 . K, it will 

 become 



^ = 1-6. K; 

 consequently 



As we have taken the second and the centimetre as the units of 

 time and length, g will be equal to 980'9 ; and this value being 

 substituted in the above expression, it will finally become 



D = 70-87. K\/^. 

 From this expression, and that of 5— i given by the formula (2.), 

 we deduce 



£r' = _2:2? =0-001. ' 



D 70-87. Vh »/h 



Now according to the equation (1.) this quantity represents the 



error we commit in supposing yx = l? or L = </; it is evident that 



this error is independent of the diameter of the orifice, but that it 

 varies with the charge, and that it is less in proportion as the 

 strength of the charge is greater ; it is also evident, that for it 

 not to be very small, an extremely small value must be given to 

 the charge ; for when the charge is too small, either the flow 

 does not take place, or it ensues drop by drop, in both which 

 cases the nature of the phjenomenon is changed, and cannot be 

 referred to the transformation of a cylinder. We shall therefore 

 suppose that the value of the charge is 4 centims. for instance, 

 which is certainly a small value, and which is slightly greater 

 than the least of the values employed by Sa:vart in his experi- 

 ments. We shall then have 



^=0-0005; 



and transferring this value to the equation (1.), we shall find 



g = 1 + 0-0005, 



or rather 



L-D =0-0005. D. 



Thus, according to this result, whatever the diameter of the 

 orifice may be with the feeble charge of 4 centims., the length 



