DISCONTINUOUS FUNCTIONS. 259 



Hence, 



f (x) := e X ... between the limits x = o and x := a 



fi (x) = a e X = a and x ^ b 



£2(0;) = f (c — x), X = b and x = indefinitely. 



Substituting these values in formula for two 

 breaks, we shall have — 



YA*B , Ai'B , Bi »/ \ 

 2 = ^— ex + -^. ae + — '. f (c - x) 



where, A = i + y — - and A, = l 



Ifl X 



B = 1 + tuf and B, = 1 - ^^^' 

 b u> X aw X 



Consequently, we shall obtain for the value of Y^ 



