210 REV. R. HARLEY ON SYMMETRIC PRODUCTS, AND 
+ 1443 (54443) + 26-5°@*E*SU — 8-5QEZU*. 
But 
(1055) =-5°Q°E+6-5E*, £(104411)=-3-5°Q°E +4 5E', 
5 (103322)=5E', 3(9641)=4.5E4, ¥(9524)=-6-5°Q°E 
+4.5E', 5(95821)=—5E*, £(94831)=2-5E*, (94322) 
=2.5E!, 3(8782)=-6-5°Q°E+4.5E!, (8651) =4-5Et, 
3 (86321) =4.5E', ¥(85511)=-3-5°QE+5E!, 5(8543) 
=4.5E, 3(85421)=-5E4, 3(85322)=2-5E, 2(84431) 
=2.5E4, 3(84422)—5E!, 3(84832)=-3-5E', (83333) 
=5Et, 3(77411)=-3-55Q°H+5E', 3(77222)=2-5Et, 
3(7652)=-6-5°Q°E+4.-5E, 3(7643)=-5E!, 3(76421) 
=4.5E!, 3(76331)=2-5E!, 3(76322)=-3-5E*, 3(75521) 
=2.5E, 3(7544)=2-5E', 3(75431)=-5Et, 3(75422) 
=-3.5E!, 3(75332)=2-5E!, 3(74441)=-5E, 3(74432) 
=2.5E', 3(74333)=- 5B, =(66611)=-5°Q°E+2-5Ei, 
3(6653)=2-5E*, 3(66521)=-3-5E', 3(66431)=—3-5E!, 
3(66422)=5E*, 3(66332)—5E!, 3(6554)=-3-5Et, 
3(65531)=2-5E!, 3(65522)=5Et, 3(65441)=2-5Hs, 
3(65432)=-— 5E*, 3(65333)=-5Et, 2(64442)=— 5 Bt, 
3(64433)=5Et, 3(55541)=-5E, 3(55532)=- 5H, 
3(55442)=5E!, 3(55438)=5E', 3(54443)=- 5 Et, 
SU=0, and >U'=6-5'Q*. Hence, by substitution, we 
have 
SUF=— 158-5°Q5E+55E'; .. TAF=—5*2U! 
=158.5"Q°E — 5"Et, 
Now (Art. 32), 
DSH D tae: 
and (Art. 36 and 37) 
D,=2-5°QE, and D,=2-57Q!; 
consequently 
D,= —58-5°Q°E + 5"E!. 
43. Again: =/(83333)=5(83333)=5E‘, 5'{(77222) 
+ (72722)} =5(77222)=2-5E', &/§(75382) + (753823) 
+ (75238) + (73532) + (73523) + (73352) + (73325) 
+ (78258) + (73235) + (72533) + (72358) + (72335) 
