80 PROCEEDINGS OF SECTION A. 
The locus of points whose axes are parallel to this line is 
the conic 
i 
= COR r = eyx) a ley aa.) +o (aa, — bB,) = 0 
ee WS aIV- 
a 
= a, (OR: - ey) 
M = fi (ey1 — aaj) 
N = y¥\ (aa, — 0B) 
Let this conic cut the line 
a3 
ao Bo Yo 
in the points a’3’y’ and a’B’y"; then the axes of these 
point are the required tangents. 
We have 
a 
5+ 5 +%=0 
VE, M INN 0 
He oe ae 
/ if / 
a ee ey 
ao Bo Yo 
| eee | l 
Hence =) : p’ : am gd bk : yL—aN: aM—pBN 
il 
and 2 BN — vit 
is the required equation. 
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