334 Relation letween the Specific Grai'ltlcs and 



§ 36. Problem VI. — The quantities ly measure of any 

 number af liquors of different strengths, and their per-cent- 

 age, at a given temperature being slien, to find the perr 

 centage of the compound when reduced to that temperature. 



Practical Rule. 



Firstly, Find the tabular specific gravity of each liquor 

 ct the given temperatitre by Problem III, and multiply suck 

 quantity by Its respective specific gravity so found. 



Secondly, Find the compound corre<:pondcnt to each In. 

 Column I ; multiply each product obti/lned as above by the 

 weight of the spirit in its respective compound as found In 

 that column, and divide the product by the sum of the neights 

 of Its spirit and water. 



Thirdly, Find a liquor in Column I whose iceight of spirit 

 is to that of Its whole composition as the sum of all the quo- 

 tients obtained in the second step to that of all the products 

 obtained in the first ; and it trill be that which Is equivalent 

 to the compound produced by the mixture of all the given 

 liquors, u'hose per-centage may therefore be determined by 

 Problem II. 



Example. 



Suppose we inix .556 gallons of brandy of 111 (or 

 11 O.P.), 9i2 of 03 (or 7 U.P.), 427 of 80 (or 20 U.P.), 

 346 of 117 (or 17 O.P,), and nil of 105 (or 5 O.P.), all 

 at 67°, together 3 what will be the per-centage of the com- 

 pound ? 



Solution, 

 Firstly, 



The tabular specific gravity of 1 1 1 at 67° (by 



Prob. Ill) is = 902-44, which x 556 is -' = 50i'76 



That of 93 is = 925-04, which x 942 is - = 871-39 



That of 60 is = 939-48, which x 427 is - = 401-16 



That of 117 is = 894-33, which x 346 is - = 309*44 



That of 105 is = 9l0-25j which x 1111 is - = 1011-30 



And tlie sum of these products is - = 3095-05 

 Secondly, 



m at e7° is = 100 5p. 4- 60-0.^ W. and 501-7(7 x 100 ^ 160-05 = 313-50 



93 is = 100 3p. -j- 95.S3 W. and 871-39 X 100 ~ 1 9.5-83 = 444-97 



80 - - - is = 100 \V. -f- 76.'J4 Sp. and 40M6 X "<>-24 — 170'-1.'4 = 173-54 



117 is = 10<) Sp. -j- 50-49 W. and 309-14 x iOO -=- 1,50-49 = 205-62 



105 - - - is = 100 Sp. -\- 70-06 W. and 101 1-30 x 100 ~ 170-66 = 592-58 



And the sum of these quotients is = 1730-^1 



Thirdly, 1730-31 : 3095-05 : : 100 : 178-88S. 



The 



