SIMPLE DIVISION. • 27 



2. Find how many times the divisor may be had in as 

 many figures of the dividend, as are just necessary, and 

 write the number in the quotient. 



3. Multiply the divisor by the quotient figure, and set 

 the product under that part of the dividend used. 



4. Subtract 



value of which it is taken in the operation ; according as there 

 are i, 2, or 3, 8cc. figures standing before it ; and consequently 

 the true value of tiie quotient figure, belonging to that part of 

 the dividend, is also 10, 100, or 1000, Sec. times its simple 

 value. ' But the true value of the quotient figure, belonging to 

 that part of the dividend, found by the rule, is also 10, ioo» 

 or 1000, &c, times its simple value : for there are as many 

 figures set before it, as the number of remaining figures in the 

 dividend. Therefore this first quotient figure, taken in its com- 

 plete value, from the place it stands in, is the true quotient of 

 the divisor in the complete value of the first part of the divi- 

 dend. For the same reason, all the rest of the figures of the 

 quotient, taken according to their places, are each the true quo- 

 tient of the divisor, in the complete value of the several parts 

 of the dividend, belonging to each ; because, as the first figure 

 on the right hand of each succeeding part of the dividend has 

 a less number of figures, by one standing before it, so ought their 

 quodents to have 5 and so they are actually ordered : conse- 

 quently, taking all the quotient figures in order as they are 

 placed by the rule,, they make one number, which is equal to 

 the sum of the true quotients of all the several parts of the 

 dividend ; and is, therefore,, the true quotient of the whole 

 dividend by the divisor, Q:_ E. D. 



To leave no obscurity in this demonstration, I sliall illustrate 

 it by an exarnple. 



liXAMPLB. 



