Iractio^s. $^J 



PROBLEM I. 

 ?i find the greatest common measure of the terms of a fractiotti 



RULE. 



1* Range the j^uantities according to die ^diaieasions of 

 some letter, as is shewn in division. 



2. Divide the greater term by the less, and the last di- 

 vIs|oi% by the. last remainder, and so on till nothing re- 

 main ; then the divisor last used vjrill be the common 

 measure required. ^ 



Note. All the letters or figures, which are common to 

 each term of any divisor, must be rejected before such di- 

 visor is used in the operation. 



EXAlklPtES* 



I. ^o find the greatest common measure of — r-; — r". 

 or C'\-x)ca * -\-a * !x{a * 



Therefore the greatest common measure is r-j-^r. 

 a. To find the greatest common measure of — 



—2bx''—2b'-x)x * + 2hX'\-b'' 

 or ^+^. )x''\-2bx+b\x'\-h 



bx+i^' 



Therefore X'\'b is the greatest common measure. 



3. To 



