DYNAMICS AND KINEMATICS OF SUBMARINE CABLE 



1201 



Finally, we obtain the root of (99), a = 0.555 by reading off the cor- 

 responding abscissa (point C) . This value of a now serves as the starting 

 point in the iteration procedure by which we find the tension correspond- 

 ing to a given t. 



For example, for I = 1.0 (t = GOO seconds) we have the following se- 

 quence of values 



(To = 0.555 

 (Ti = 0.580 

 (72 = 0.580 



((P3 sin a)/(pi ^* = ^ [1 + (<p3 sin a) t/<p2\ 



0.212 0.00379 



0.213 0.00380 



with a converging to the value 0.580. For a = 0.580, Fig. 37 gives 



cosh a/<p2 = 0.800. 

 Hence, by (98b) for i - 1.0 



Ts = 1.80, 

 and Ts = 1.80 wh or 7,600 pounds. 



"©. 



as 



1.0 1.5 



2.0 



2.5 



03 (o") 



Fig. 38 — Variation of sin a — y\ with a. 



