EXAMPLES XVII 265 



P.ivadth of strip = 0-9* 



Area of figure = 42-48 x 0-9 = 88-19 sq. in. 



Area of first derived figure - 20-75 x 0-9 = 18-67 sq. in. 



Area of second derived figure = 12-69 x 0-9 = 11-42 sq. in. 



18-67 

 X 8l9 

 = 4-899 in. 

 I oy = 9 2 x 11-42 



= 925-1 inch units 



EXAMPLES XVII 



(1) The following values of y and x being given, tabulate Sy/Sx 

 and y &r in each interval. If y 8a? be called 8A, tabulate the 

 values of A if A is where x = 0. (B. of E., 1905.) 



(2) By tabulation give approximately a table of values of 

 j- and \y dx if the following values of x and y are given. 

 (B. of E., 1908.) 



(8) The following values of x and y being given, tabulate 

 in each interval, also SA = y 8# and A = \y dx. (B. of E., 1910.) 



(4) The diameter of a circle of 5 inches radius is divided into 

 20 equal parts, and ordinates are drawn to the circle from each 

 point of division. Calculate the lengths of these ordinates. Find 

 the area of the circle (1) using the Trapezoidal Rule, (2) using 

 Simpson's Rule and calculate the percentage error in each case. 



