TRANSMISSION LINE 403 



The charging current of the line is 

 Ic = E'jb c 



-j&), .... (369) 



and the current from the generator is 



1 G = I +1. = E^g -jb + J6 C 1 + --(g - j&)- (370) 



I ^o gS 



t : - sAMA, - TKM^ 



n s 



-=P E- ^ 



T _ . _j 



FIG. 376. Single-phase transmission line with capacity. 

 The terminal e.m.f. of the generator is 



-jb. (371) 



For lines of small capacity the last term may be neglected and 

 equation 371 reduces to 



. (372) 



(3) A single-phase transmission line delivers 10,000 kilowatts at 

 100,000 volts to a receiver circuit of 85 per cent power factor; 

 find] the voltage current and power factor at the generating end 

 of the line, the impedance drop and power loss in the line and 

 the charging current. Find also the generator voltage required 

 to give a receiver voltage of 100,000 volts at no load. 



Length of line = 100 miles. 

 Size of wire = No. 000 B. & S. copper. 

 Diameter of wire = 2 R = 0.41 inch. 

 Distance between wires = D = 72 inches. 

 Frequency = 60 cycles per second. 



