TRANSMISSION LINE 405 



The load delivered to the receiver is 



P = El cos <j> = 10,000,000 watts, 

 but E = 100,000 and cos < = 0.85; 



therefore, the current in the receiver circuit is 



~ 



P 10,000,000 



,, 

 100,000 X 0.85 " 



the power component is 



IP = I cos = 117 X 0.85 = 100 amperes; 

 the wattless component is 



I w = I sin <{> = V/ 2 "- 7p 2 = Vll7 2 - 100 2 = 60 amperes. 

 The admittance of the receiver is 



the conductance is 



_7_cos^_ 100 

 ~E " 



and the susceptance is 



7 sin <ft 60 





The generator voltage is, by equation 371, 



E = E^l + (r+jx)(g - J&+4') +3 b f 

 and substituting the values obtained above 



Eb = E j 1 + (68 + 148 j) (o.OOl - 0.0006 j + a 







+ j (68 + 148 j) 2 (0.001 - 0.0006 j) 



and simplifying 



E G = E (1.1355 - 0.1162 j), 

 and the absolute value is 



EG = ^v / (1.1355) 2 +(0.1162) 2 



= 100,000 X 1.1355 = 113,550 volts. 



