T A B L E XI. 



NOMBRE 2 a. 



DIVISEURS 8 /Z 4-3,8/2 + 5. 



e ■\- ii6 «= 



I 2 I + 4 -}- I 



I oo -f- 2 5 -f I 



8i + 36 + 9 



81+36+9 



I 



\ 



Crj— 4{/ + r2J + 3{74-r 



/ri 



3y + 42f7 ,, ,, 



6 =" 4- 2 1 ^^ f '^^'^ decomposables, 



ioy^ + 4yz+i3 z=^9y^ + (y+2z)= + 92? 



49 + 49 + 3^ 



I 2 I -f 9 -L. 4 



I 00 + 2 5 + 9 



81+49 + 4 



il +36-1-25 



^' + 134 «' 



■ 2j'^ + 67f = + 3^/ + (3._3^/ + 49^^ 

 iij'=+i6jKt+i8f=^3jK + {/+rjK + 4^7 + 6^ + ^7 

 5^= + 8^^ + 30^=0+ 2 ^/ + (^2y+7/+ 25 f 

 3J' + 4jrl-46fr=^rj'— c/ + Cr + 6{/ + (rj— 3^^ 



/" + 142 z^^ 

 IIJK=^+20j^+22f ^f3JK+3^/ + 0+3^/ + ('y— i^/ 



I 2 I + 2 5 -•- 4 

 1 00 + 49 + I 



100+25 + 25 



1 00 + 2 5 -i- 2 5 



100 + 25 + 25 

 1 00 + 2 5 + 2 5 



100 + 49 + 9 

 1 2 1 + 3 6 + I 



/' + 150/^' 



(r3j+2{/+ry-{;'+ry— 3î/ 



iiy^ + 4j^+i4^- = .Y3j— {/ + 6' + 3^/ + (fj + 2t/ 

 c J' + {/ + 6—3 î/ + (Tj + ^ iT 



2y= + 75Z*.::r(y+5z)^ + (y— 52)^+252^ 



3y^+50z"=:(y+5z)^ + (y— 5z)= + y^ 

 5y^+3oz=z=(2y + z)=+(y— 2z)^+25z^ - 



e + 158/^^ 



3j^ + 4.rî+54f = Cy+5{r + ry— H/+6 + 2tr 



81 + 81 +4 

 121 + 36+9 

 81+49+36 



t" + 166 A^- 

 1 jK' + 83 f = o + ^y + rj— {/ + 8 1 f 



5J'^ + 4.r{+34f==r2.y+3{/-^6— 4{/ + 9f 

 i3jy'^ + 8y^+i4f=Oj + M/ + r2.j'— {7 + 9f 



