CONTINUOUS-CURRENT WINDINGS 151 



to be replaced by a single conductor. Thus we have 6 " equiva- 

 lent " conductors per slot, or 



57x6 = 342 

 face conductors. 



340 or 344 OK 

 y - = 85 or 86. 



Let us examine whether it will be practicable to use 



We should go from 1 to 86 at the back end, and also from 3 to 88 

 and from 5 to 90. Since 1, 3, and 5, together with 86, 88, and 90, 

 must constitute a form-wound coil ; then if 1, 3, and 5 occupy the 

 top half of some slot, say slot 1, then 86, 88, and 90 must occupy 

 the bottom half of some other slot. Slot 1 contains conductors 1, 

 2, 3, 4, 5, and 6. The slot containing conductors No. 86, 88, and 90 

 in its lower half, must contain conductors 85, 87, and 89 in its 

 upper half. Thus the first 90 conductors must occupy an integral 

 number of slots. Evidently this condition is fulfilled, for 



90 IK 

 - = 15. 



Thus while conductors 1, 3, and 5 occupy the top half of slot 1, 

 conductors 86, 88, and 90 occupy the bottom half of slot 15. But 

 suppose we had required five segments per slot, then 



= 10x57 = 570 



% =572 or 568 



y = 143 or 142. 



Suppose we wish to take yf= 143 and yb = 143. Then conductors 

 1, 3, 5, 7, and 9 go to conductors 144, 146, 148, 150, and 152. 

 Thus if 1 is the upper left-hand conductor of slot 1, then 152 

 ought to be the slot holding the lower and right-hand side of the 

 coil; but since 152 is not divisible by 10 without a remainder, 

 that is not the case, and hence it will not do to employ a pitch of 

 143 at both ends. But if we change yb to 141, then we have 1, 3, 

 5, 7, and 9 connected to 142, 144, 146, 148, and 150. Hence while 

 conductor No. 1 is the upper left-hand conductor of slot 1, con- 

 ductor No. 150 is the lower right-hand conductor of slot 15, 

 which is the required condition. The component turns will also 



