CONSOLIDATED STEEL CORPORATION 



163 



DEFLECTION COEFFICIENTS 

 FOR UNIFORMLY DISTRIBUTED LOADS 



Fiber Stress, 16,000 Pounds per Square Inch 



These coefficients furnish a convenient means of finding the deflection of 

 steel sections under their uniformly distributed safe loads for a maximum 

 fiber stress of 16,000 pounds per square inc^C^ 



To find the deflection of a steel beany grider, or other section which is sym- 

 metrical about its neutral axis, under theNahotfe condition of loading, divide the 

 deflection coefficient found in the above table for the given span by the depth 

 of the beam in inches. The quotient will be the deflection in inches. 



To find the deflection of an angle or other section which is not symmetrical 

 about its neutral axis under the above condition of loading, divide the deflec- 

 tion coefficient in the table for the given span by twice the greatest distance, 

 in inches, of the neutral axis from the outside fiber in the direction of bending. 



Under uniformly distributed loading corresponding to other intensities of 

 stress the deflection can be found by simple proportion. Thus, for a uniformly 

 distributed load producing a fiber stress of 12,000 pounds per square inch the 

 deflection will be if ${$ or % of that found by the use of the above coeffi- 

 cients. 



