FLA ME TEMPERA T URES. 1 7 l 



3. Marsh Gas. This gas requires 4 times its weight of 

 oxygen, and produces 2.25 parts of aqueous vapor and 2.75 

 parts of carbonic acid. If air is used, 13.39 parts of nitrogen 

 are introduced. The heat of combustion is 13343 calories. 



The equations are, then, 



2.25 X 0.479 + 2.75 X 0.217 

 for oxygen and 



_ -^3343 _ ! _ 



2.2$ X 0.479 + 2-75 X 0.217+ 13.39 X 0.244 



for combustion in air. 



Olefiant gas, acetylene, etc., can be calculated similarly. 



With a mixed gas, i.e., one containing several gases, account 



must be taken of each one separately. Producer gas will be 



given as an example. 



4. Producer Gas. The producer gas taken will be assumed 



to have the following composition by volume : 



Carbonic oxide ............... 21.0 per cent. 



Hydrogen ................... 11.5 " " 



Marsh gas ..................... 2.0 " 



Carbonic acid ............... ... 6.0 " " 



Nitrogen _____ ................. 59.5 " " 



i oo.o 



First obtain the weight of the constituents. (See the tables,) 

 0.21 X 1.2515 =0.2628 

 o. 1 15 X 0.0896 = 0.0103 

 0.02 X 0.7155 0.0143 

 0.06 X 1.9666=0.1360 

 0.595 X 1.2561 =0.7474 



CO 2 H 2 O N 



CO 0.2628 produces ____ 0.413 .... 0.502 



H 0.0103 " ........ 0.093 0.276 



CH 4 0.0143 " ---- 0.039 0.032 0.192 



CO, 0.1360 " .... 0.136 .... 



N 0.7474 .... .... 0.747 



0.588 0.125 



