E 



Now if J~- 15 ; A = 600 and f s =20,000 (Usin* 



f-'C 



twisted steel or patented bar. ) 

 Substituting in (2) j- : x :: ~- : (dtx) (4) 



20.000 

 and 600 :.r:: 15 - : (dex) 



(d-e) 



3.22 (5) 



By proper tests /: v and c can be determined for the 

 material to be used and working values of f s and f c 

 obtained. These values substituted in (4) will give a 

 tliilVrent value of j. 



To determine the value of (de) substitute the value of 

 (x) in the equation 



which iifc =^600 Ib. per sq. in. 



Compression =Tension, then * c x . b=A s ./, using 



20,000 Ib. per sq. in. on the iteel. 

 600. jr X\2=A S . 20,000 . . 3600 9 



2 20,000* 50 ' 



