84 CONSTANT-VOLTAGE TRANSMISSION 



Conditions given: 

 E 8 = 2,200 

 E = 2,000 

 R = 1.69 

 X = 2.16 



1,000X240 



P = - = 120 total amperes. 

 2,000 



COS0 = 0.80 



Then, from (3), Table I, 



<*i = 7-50 

 bi = 4,320 

 and ci = 14,400 X 7.50 + 4,ooo X 120 X 1.69 + 



4,000,000 4,840,000 

 = 79>ooo 



Then = 4,3 20 ~ 4,320* ~ 7 50 X 79,000 



7-50 



= +9.2 total amperes. 



Therefore the reactive Kva. in the line at the receiver 

 end are leading. 



The reactive Kva. of synchronous motors are, by (6), 

 Table I, 



2 X 9. 2 + 2 X ^~ X 120 = 198 Kva. 



O. 5 



The power-factor at the generators is, by (10), 



240,000+ 14,490 X 1.69 

 100 ~ 2,200 X 120.3 =99 ' 9% 



The reactive Kva. at the generators are, by (n), 



2,000 X 9 . 2 - 14,490 X 2 . 16 _ 



13 

 1,000 



Therefore, the generator P. F. is lagging. 

 The efficiency of the line, by (12), is 

 ICQ X 240,000 __ 

 240,000 + 14,490 X 1.69 "" 9 ' 7 



