226 



ELECTRICAL MACHINERY 



currents and is shown in Fig. 136 by 01 which lags behind 

 the impressed e.m.f., OE, by the angle $. 



It is evident that 01 may be considered as made up 

 of two components, OA and AI. These two components 

 may easily be obtained from the branch currents by observ- 

 ing that 



and 



OA =01 1 COS $1+0/2 COS <j>2, 



AI = 01 1 sin 4>i 0/2 sin $ 



FIG. 135. Inductance and 

 Capacity in Parallel. 



FIG. 136. Current in the Circuit 

 Shown in Fig. 135. 



There is also another method for solving parallel circuits 

 by a scheme involving the use of complex quantities but 

 it is not thought desirable to introduce it in this elementary 

 text. 



55. Resonance. In circuits containing inductance and 

 capacity, these two quantities may be so proportioned that 



(62) 



In such a case the inductance reaction becomes just 

 equal to the capacity reaction and hence these two reactions 

 will just neutralize each other, as they are opposite in phase. 



