STRESS DUE; TO ECCENTRIC LOADING 



147 



STRESS DUE To ECCENTRIC LOADING 



The stress in The extreme fibre due to eccentric loading will be 



fe = 



Pey. 



Eccentric stress in upper fibre 



r 95300X1.44X3-81 



fe = ~~ 95300X358* = - 3347 lbs.(tension) 



99.8 ~| ox 20 000 000 



Eccentric stress in lower fibre 



f e = 6^44 x 3347. = + 5657 Ibs.(compression) 



The resultant stress due to eccentric loading and weight will be 

 f. = fe+fw 



=-334-7+1100 =-24-7 IDS- in upper fibre. 

 =+5657-1860 =+3797 Ibs- in lower fibre. 



The maximum stress in the member due to direct loading, weight 

 Of member and eccentric loading will occur in the lower fibre and 

 will be f, .< 



To determine the position of the pin so that stress due to weight 

 will neutralize stress due to eccentric loading make 



Pe'=WI sine .where e' is the distance of the pin 

 oelow rhe neutral axis. 



Substituting and solving , 95300 xe'= ( 1585x358 x-633) 



e'=.48" 



STRESS DUE To WIND MOMENT 



>N M 



a=8" 



Portal.Columns Hinged. Portal.Columns Fixed. Windward Pedestal. 

 (a) (b) (c) 



