ALTERNATING GENERATORS AND SYNCHRONOUS MOTORS. 117 
kxmxnxZxCxF, k _Nxp 
mx EX C= 10" =F0'% 0 ——xmxZxCxFf,, 
is obtained, where the value of the frequency n is replaced 
x y 
by the expression 60 L 
Finally, since mX E X C= KVA. X 10°, we have: 
KVA. k = 
WV Semin 2 x CX 2p X xX 20 x 107 (F5) 
190. Choice of Armature Flux.—fFor alternators with 
similar windings and the same pole are ratios, the form 
factor is constant and so there is obtained the expression : 
KVA. | 
| WN = Constant Xm X Z XC X 2p X F, .. (36) 
This equation indicates that with the choice of the total 
armature flux, the number of the armature conductors is 
fixed and it is a simple matter to follow up the right 
course of calculation for other compromises required. 
In Example 25 of Par. 188, Equation ($5) indicates a 
value for the armature ampere conductors, where k is 
assumed to be 2.2, 
3=m X Z X C X 100 X 10° a and m X Z X C = 163,600. 
Or if the machine is three phase, with a phase voltage of 
2,000, then the current C = 50 amperes, m = 3, and the 
163,600 
3X 50 
number of armature conductors per phase = 
= 1,087. 
191. Determination of Bore.—For the determination of the 
most suitable bore of the armature, the data given in 
Fig. 63 forms a sound basis to work upon, and indicates 
the number of armature ampere conductors per one inch 
length of the periphery. 
This peripheral density is defined as 
(Z2C)=mxZx c 
Drei (37) 
. 
